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Mathematics
Problem
The 2nd derivative of
a
sin
3
t
a \sin^3 t
a
sin
3
t
with respect to
a
cos
3
t
a \cos^3 t
a
cos
3
t
at
t
=
π
4
t = \frac{\pi}{4}
t
=
4
π
is (a)
4
2
3
a
\frac{4\sqrt{2}}{3a}
3
a
4
2
(b) 2 (c)
1
12
a
\frac{1}{12a}
12
a
1
(d) None of these
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