Mathematics

Problem

0 < x < \pi

and

\cos x + \sin x = \frac{1}{2}

, then

\tan x

is a.

\frac{(4 - \sqrt{7})}{3}

-\frac{(4 + \sqrt{7})}{3}

\frac{(1 + \sqrt{7})}{4}

\frac{(1 - \sqrt{7})}{4}