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Mathematics
Mathematics
Problem
If
cos
θ
=
−
3
2
\cos \theta = -\dfrac{\sqrt{3}}{2}
cos
θ
=
−
2
3
and
180
∘
<
θ
<
360
∘
180^{\circ} < \theta < 360^{\circ}
18
0
∘
<
θ
<
36
0
∘
, answer the following: a. (a) Determine
sin
θ
\sin \theta
sin
θ
. b. (b) Identify the quadrant in which
θ
\theta
θ
lies. c. (c) Find the smallest positive value of
θ
\theta
θ
(in degrees) that satisfies the given information.
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