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Mathematics
Mathematics
Problem
If
sin
−
1
x
+
cot
−
1
(
1
2
)
=
π
2
\sin^{-1}x + \cot^{-1}\left(\frac{1}{2}\right) = \frac{\pi}{2}
sin
−
1
x
+
cot
−
1
(
2
1
)
=
2
π
, then
x
x
x
is equal to (a) 0 (b)
1
5
\frac{1}{\sqrt{5}}
5
1
(c)
2
5
\frac{2}{\sqrt{5}}
5
2
(d)
3
2
\frac{\sqrt{3}}{2}
2
3
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