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Physics
Physics
Problem
In a nuclear reaction
8
19
O
⟶
8
19
O
^{19}_{8}O \longrightarrow ^{19}_{8}O
8
19
O
⟶
8
19
O
;
Δ
E
=
4.5
×
10
8
kJ mol
−
1
\Delta E = 4.5 \times 10^{8} \text{ kJ mol}^{-1}
Δ
E
=
4.5
×
1
0
8
kJ mol
−
1
. The mass difference in excited state of
19
O
^{19}O
19
O
and ground state of
19
O
^{19}O
19
O
per mol in mg is.....
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