Mathematics

Mathematics

Problem

Simplify sec⁡2θ−1csc⁡θ\dfrac{\sec^2\theta-1}{\csc\theta} so that the final answer is expressed only in terms of sin⁡θ\sin\theta. a) sin⁡θ1+sin⁡2θ\dfrac{\sin\theta}{1+\sin^2\theta} b) sin⁡3θ1−sin⁡2θ\dfrac{\sin^3\theta}{1-\sin^2\theta} c) sin⁡θ1−sin⁡2θ\dfrac{\sin\theta}{1-\sin^2\theta} d) 1−sin⁡2θsin⁡θ\dfrac{1-\sin^2\theta}{\sin\theta}

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