Problem

Problem

A solution buffered at pH 9.30 is 0.0050 M in both Ba2+^{2+} and Sr2+^{2+}. The carbonate ion concentration in the buffer is 1.0×10−31.0\times10^{-3} M. Solubility products are Ksp(BaCO3)=5.1×10−9K_{sp}(\text{BaCO}_3)=5.1\times10^{-9} and Ksp(SrCO3)=1.0×10−10K_{sp}(\text{SrCO}_3)=1.0\times10^{-10}. Which metal ion will selectively precipitate as its carbonate under these conditions? Provide only the ion’s chemical symbol.

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