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Introduction to Electrodynamics
· Problem 1.6
Vector Analysis — David J. Griffiths
Physics · triple-products
Problem
Prove that
[
A
×
(
B
×
C
)
]
+
[
B
×
(
C
×
A
)
]
+
[
C
×
(
A
×
B
)
]
=
0
[\mathbf{A} \times (\mathbf{B} \times \mathbf{C})] + [\mathbf{B} \times (\mathbf{C} \times \mathbf{A})] + [\mathbf{C} \times (\mathbf{A} \times \mathbf{B})] = \mathbf{0}
[
A
×
(
B
×
C
)]
+
[
B
×
(
C
×
A
)]
+
[
C
×
(
A
×
B
)]
=
0
. Under what conditions does
A
×
(
B
×
C
)
=
(
A
×
B
)
×
C
\mathbf{A} \times (\mathbf{B} \times \mathbf{C}) = (\mathbf{A} \times \mathbf{B}) \times \mathbf{C}
A
×
(
B
×
C
)
=
(
A
×
B
)
×
C
?
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