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Physics
Physics
Problem
Taking
G
=
6.67
×
10
−
11
N m
2
kg
−
2
G = 6.67\times10^{-11}\,\text{N m}^2\text{kg}^{-2}
G
=
6.67
×
1
0
−
11
N m
2
kg
−
2
,
M
⊕
=
6.0
×
10
24
kg
M_{\oplus}=6.0\times10^{24}\,\text{kg}
M
⊕
=
6.0
×
1
0
24
kg
and
R
⊕
=
6.4
×
10
6
m
R_{\oplus}=6.4\times10^{6}\,\text{m}
R
⊕
=
6.4
×
1
0
6
m
, calculate the altitude (above Earth’s surface) of a geostationary satellite. Assume the satellite’s orbital period equals
24
h
24\,\text{h}
24
h
. a)
4.2
×
10
4
km
4.2\times10^{4}\,\text{km}
4.2
×
1
0
4
km
b)
2.4
×
10
4
km
2.4\times10^{4}\,\text{km}
2.4
×
1
0
4
km
c)
3.6
×
10
4
km
3.6\times10^{4}\,\text{km}
3.6
×
1
0
4
km
d)
1.5
×
10
4
km
1.5\times10^{4}\,\text{km}
1.5
×
1
0
4
km
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