Physics

Physics

Problem

Taking G=6.67×10−11 N m2kg−2G = 6.67\times10^{-11}\,\text{N m}^2\text{kg}^{-2}, M⊕=6.0×1024 kgM_{\oplus}=6.0\times10^{24}\,\text{kg} and R⊕=6.4×106 mR_{\oplus}=6.4\times10^{6}\,\text{m}, calculate the altitude (above Earth’s surface) of a geostationary satellite. Assume the satellite’s orbital period equals 24 h24\,\text{h}. a) 4.2×104 km4.2\times10^{4}\,\text{km} b) 2.4×104 km2.4\times10^{4}\,\text{km} c) 3.6×104 km3.6\times10^{4}\,\text{km} d) 1.5×104 km1.5\times10^{4}\,\text{km}

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