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Mathematics
Mathematics
Problem
A function
x
(
t
)
x(t)
x
(
t
)
satisfies
d
x
d
t
=
t
+
1
t
(
t
−
3
)
\displaystyle \frac{dx}{dt}=\frac{t+1}{t(t-3)}
d
t
d
x
=
t
(
t
−
3
)
t
+
1
and
x
(
1
)
=
0
x(1)=0
x
(
1
)
=
0
. For
t
>
1
t>1
t
>
1
, at what value of
t
t
t
does
x
(
t
)
=
ln
2
x(t)=\ln 2
x
(
t
)
=
ln
2
? Round your answer to the nearest tenth. a)
t
≈
6.9
t \approx 6.9
t
≈
6.9
b)
t
≈
8.8
t \approx 8.8
t
≈
8.8
c)
t
≈
5.6
t \approx 5.6
t
≈
5.6
d)
t
≈
9.6
t \approx 9.6
t
≈
9.6
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