Chemistry

Problem

Three moles of electrons are passed through three solutions in succession containing

\text{AgNO}_3

\text{CuSO}_4

and

\text{AuCl}_3

, respectively. The molar ratio of amounts of cations reduced at cathode will be (a) 1 : 2 : 3 (b)

\frac{1}{1} : \frac{1}{2} : \frac{1}{3}