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JEE Advanced 2015 Paper 2 Physics Q2
Physics · Foundations & Measurement
Problem
The energy of a system as a function of time
t
t
t
is given as
E
(
t
)
=
A
2
exp
(
−
α
t
)
E(t)=A^2\exp(-\alpha t)
E
(
t
)
=
A
2
exp
(
−
α
t
)
, where
α
=
0.2
s
−
1
\alpha=0.2\,\mathrm{s}^{-1}
α
=
0.2
s
−
1
. The measurement of
A
A
A
has an error of
1.25
%
1.25\%
1.25%
. If the error in the measurement of time is
1.50
%
1.50\%
1.50%
, the percentage error in the value of
E
(
t
)
E(t)
E
(
t
)
at
t
=
5
s
t=5\,\mathrm{s}
t
=
5
s
is
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