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Mathematics
Mathematics
Problem
The equation
sin
4
x
−
(
k
+
2
)
sin
2
x
−
(
k
+
3
)
=
0
\sin^4 x - (k+2)\sin^2 x - (k+3) = 0
sin
4
x
−
(
k
+
2
)
sin
2
x
−
(
k
+
3
)
=
0
possesses a solution if a.
k
>
−
3
k > -3
k
>
−
3
b.
k
<
−
2
k < -2
k
<
−
2
c.
−
3
≤
k
≤
−
2
-3 \le k \le -2
−
3
≤
k
≤
−
2
d.
k
k
k
is any (+ve) value
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