Physics

Problem

Consider the reaction

{}_{92}^{235}\text{U} + {}_{0}^{1}\text{n} \rightarrow {}_{57}^{145}\text{La} + {}_{x}^{y}\text{X} + 3{}_{0}^{1}\text{n}

. What is

x

and

y

? Calculate the energy released. (Binding energy per nucleon:

{}_{92}^{235}\text{U} = 7.59 \text{ MeV}

{}_{57}^{145}\text{La} = 8.26 \text{ MeV}

\text{X} = 8.56 \text{ MeV}