lim⁡x→0[sin⁡(x+a)+sin⁡(a−x)−2sin⁡axsin⁡x]=\lim_{x \rightarrow 0} \left[ \frac{\sin(x+a) + \sin(a-x) - 2\sin a}{x \sin x} \right] =…

Mathematics

Problem

lim⁡x→0[sin⁡(x+a)+sin⁡(a−x)−2sin⁡axsin⁡x]=\lim_{x \rightarrow 0} \left[ \frac{\sin(x+a) + \sin(a-x) - 2\sin a}{x \sin x} \right] = (a) sin⁡a\sin a (b) cos⁡a\cos a (c) −sin⁡a-\sin a (d) 12cos⁡a\frac{1}{2} \cos a

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