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Problem
Problem
ABC is a triangle such that
sin
(
2
A
+
B
)
=
sin
(
C
−
A
)
=
−
sin
(
B
+
2
C
)
=
1
/
2
\sin(2A+B) = \sin(C-A) = -\sin(B+2C) = 1/2
sin
(
2
A
+
B
)
=
sin
(
C
−
A
)
=
−
sin
(
B
+
2
C
)
=
1/2
. If A, B and C are in AP, then the value of A, B and C are a.
45
∘
,
60
∘
,
75
∘
45^\circ, 60^\circ, 75^\circ
4
5
∘
,
6
0
∘
,
7
5
∘
b.
30
∘
,
60
∘
,
90
∘
30^\circ, 60^\circ, 90^\circ
3
0
∘
,
6
0
∘
,
9
0
∘
c.
20
∘
,
60
∘
,
100
∘
20^\circ, 60^\circ, 100^\circ
2
0
∘
,
6
0
∘
,
10
0
∘
d. None of these
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