Chemistry

Problem

Taking the wavelength of first Balmer line in hydrogen spectrum (

n = 3

n = 2

) as

660 \text{ nm}

, the wavelength of the 2^nd Balmer line (

n = 4

n = 2

) will be; a.

889.2 \text{ nm}

488.9 \text{ nm}

642.7 \text{ nm}

388.9 \text{ nm}