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Problem If y = a log x + b x 2 + x y = a \log x + bx^2 + x y = a log x + b x 2 + x x = 1 x = 1 x = 1 x = 2 x = 2 x = 2 ( a , b ) = (a, b) = ( a , b ) = ( 1 , 1 2 ) \left(1, \frac{1}{2}\right) ( 1 , 2 1 ) ( 1 2 , 2 ) \left(\frac{1}{2}, 2\right) ( 2 1 , 2 ) ( 2 , − 1 2 ) \left(2, \frac{-1}{2}\right) ( 2 , 2 − 1 ) ( − 2 3 , − 1 6 ) \left(\frac{-2}{3}, \frac{-1}{6}\right) ( 3 − 2 , 6 − 1 ) ( 1 , 1 2 ) \left(1, \frac{1}{2}\right) ( 1 , 2 1 ) ( 1 2 , 2 ) \left(\frac{1}{2}, 2\right) ( 2 1 , 2 ) ( 2 , − 1 2 ) \left(2, \frac{-1}{2}\right) ( 2 , 2 − 1 ) ( − 2 3 , − 1 6 ) \left(\frac{-2}{3}, \frac{-1}{6}\right) ( 3 − 2 , 6 − 1 ) Browse the problem library