Physics

Problem

For a metal surface the stopping potential is

2.0\,\text{V}

when light of frequency

6\times10^{14}\,\text{Hz}

is used. If the same metal is illuminated with light of frequency

9\times10^{14}\,\text{Hz}

, the new stopping potential will be a)

5.0\,\text{V}

4.0\,\text{V}

3.0\,\text{V}

2.0\,\text{V}