Mathematics

Mathematics

Problem

Let the eccentricity of the hyperbola x2a2−y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 be reciprocal to that of the ellipse x2+4y2=4x^2 + 4y^2 = 4 . If the hyperbola passes through a focus of the ellipse, then a. the equation of the hyperbola is x23−y22=1\frac{x^2}{3} - \frac{y^2}{2} = 1 b. a focus of the hyperbola is (2,0)(2, 0) c. the eccentricity of the hyperbola is 53\sqrt{\frac{5}{3}} d. the equation of the hyperbola is x2−3y2=3x^2 - 3y^2 = 3

Browse the problem library