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Mathematics
Mathematics
Problem
If
y
=
1
+
1
x
2
1
−
1
x
2
y=\frac{1+\frac{1}{x^{2}}}{1-\frac{1}{x^{2}}}
y
=
1
−
x
2
1
1
+
x
2
1
, then
d
y
d
x
\frac{d y}{d x}
d
x
d
y
is equal to: a)
−
4
x
x
2
−
1
\frac{-4 x}{x^{2}-1}
x
2
−
1
−
4
x
b)
1
−
x
2
4
x
\frac{1-x^{2}}{4 x}
4
x
1
−
x
2
c)
−
4
x
(
x
2
−
1
)
2
\frac{-4 x}{\left(x^{2}-1\right)^{2}}
(
x
2
−
1
)
2
−
4
x
d)
4
x
x
2
−
1
\frac{4 x}{x^{2}-1}
x
2
−
1
4
x
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