Physics

Problem

Electrons are accelerated through a potential difference V and protons are accelerated through a potential difference 4 V. The de-Broglie wavelengths are

\lambda_e

and

\lambda_p

for electrons and protons respectively. The ratio of

\frac{\lambda_e}{\lambda_p}

is given by : (given

m_e

is mass of electron and

m_p

is mass of proton). a.

\frac{\lambda_e}{\lambda_p} = \sqrt{\frac{m_p}{m_e}}

\frac{\lambda_e}{\lambda_p} = \sqrt{\frac{m_e}{m_p}}

\frac{\lambda_e}{\lambda_p} = \frac{1}{2}\sqrt{\frac{m_p}{m_e}}

\frac{\lambda_e}{\lambda_p} = 2\sqrt{\frac{m_p}{m_e}}

Browse the problem library