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Mathematics
Mathematics
Problem
Prove De Moivre's theorem,
(
cos
θ
+
i
sin
θ
)
n
=
cos
n
θ
+
i
sin
n
θ
(\cos \theta + i \sin \theta)^n = \cos n\theta + i \sin n\theta
(
cos
θ
+
i
sin
θ
)
n
=
cos
n
θ
+
i
sin
n
θ
, for every positive integer
n
n
n
.
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