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Physics
Physics
Problem
The average kinetic energy of a nitrogen molecule in a sample is
6.20
×
10
−
21
J
6.20\times10^{-21}\,\text{J}
6.20
×
1
0
−
21
J
. Using
k
B
=
1.38
×
10
−
23
J
K
−
1
k_{\text B}=1.38\times10^{-23}\,\text{J}\,\text{K}^{-1}
k
B
=
1.38
×
1
0
−
23
J
K
−
1
, determine the temperature of the gas in kelvins.
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