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Mathematics
Mathematics
Problem
If
tan
−
1
x
−
1
x
+
2
+
tan
−
1
x
+
1
x
+
2
=
π
4
\tan^{-1} \frac{x-1}{x+2} + \tan^{-1} \frac{x+1}{x+2} = \frac{\pi}{4}
tan
−
1
x
+
2
x
−
1
+
tan
−
1
x
+
2
x
+
1
=
4
π
, then
x
=
x =
x
=
(a)
1
2
\frac{1}{\sqrt{2}}
2
1
(b)
−
1
2
-\frac{1}{\sqrt{2}}
−
2
1
(c)
±
5
2
\pm\sqrt{\frac{5}{2}}
±
2
5
(d)
±
1
2
\pm\frac{1}{2}
±
2
1
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