Mathematics

Mathematics

Problem

Let S1S_1 be the sum of first 2n2n terms of an arithmetic progression. Let S2S_2 be the sum of first 4n4n terms of the same arithmetic progression. If (S2−S1)(S_2 - S_1) is 1000, then the sum of the first 6n6n terms of the arithmetic progression is equal to (a) 1000 (b) 3000 (c) 5000 (d) 7000

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