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Mathematics
Mathematics
Problem
A particle’s velocity for
0
≤
t
≤
8
0\le t\le 8
0
≤
t
≤
8
seconds is
v
(
t
)
=
a
t
2
−
6
t
+
4
v(t)=at^{2}-6t+4
v
(
t
)
=
a
t
2
−
6
t
+
4
meters per second. The particle starts at position
x
=
0
x=0
x
=
0
and is again at
x
=
0
x=0
x
=
0
when
t
=
8
t=8
t
=
8
. Determine the value of the constant
a
a
a
.
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