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Mathematics
Mathematics
Problem
If in two triangles ABC and PQR,
A
B
Q
R
=
B
C
P
R
=
C
A
P
Q
\frac{AB}{QR} = \frac{BC}{PR} = \frac{CA}{PQ}
QR
A
B
=
P
R
B
C
=
P
Q
C
A
, then (a)
Δ
P
Q
R
∼
Δ
C
A
B
\Delta PQR \sim \Delta CAB
Δ
P
QR
∼
Δ
C
A
B
(b)
Δ
P
Q
R
∼
Δ
A
B
C
\Delta PQR \sim \Delta ABC
Δ
P
QR
∼
Δ
A
B
C
(c)
Δ
C
B
A
∼
Δ
P
Q
R
\Delta CBA \sim \Delta PQR
Δ
C
B
A
∼
Δ
P
QR
(d)
Δ
B
C
A
∼
Δ
P
Q
R
\Delta BCA \sim \Delta PQR
Δ
B
C
A
∼
Δ
P
QR
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