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Mathematics
Problem
Let the function
y
=
f
(
x
)
y = f(x)
y
=
f
(
x
)
satisfy the differential equation
d
y
d
x
=
y
tan
x
−
y
2
sec
x
\frac{dy}{dx} = y \tan x - y^2 \sec x
d
x
d
y
=
y
tan
x
−
y
2
sec
x
with condition
y
(
0
)
=
1
y(0) = 1
y
(
0
)
=
1
then
y
(
π
4
)
y\left(\frac{\pi}{4}\right)
y
(
4
π
)
is equal to - (A)
1
2
\frac{1}{2}
2
1
(B)
1
2
\frac{1}{\sqrt{2}}
2
1
(C) 0 (D) 1
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