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Chemistry
Chemistry
Problem
In the following reaction:
x
A
→
y
B
x\text{A} \rightarrow y\text{B}
x
A
→
y
B
log
10
[
−
d
[
A
]
d
t
]
=
log
10
[
d
[
B
]
d
t
]
+
0.3010
\log_{10} \left[ -\frac{d[\text{A}]}{dt} \right] = \log_{10} \left[ \frac{d[\text{B}]}{dt} \right] + 0.3010
lo
g
10
[
−
d
t
d
[
A
]
]
=
lo
g
10
[
d
t
d
[
B
]
]
+
0.3010
[JEE MAINS - ONLINE - 2019] 'A' and 'B' respectively can be : (1) n-Butane and Iso-butane (2)
C
2
H
4
\text{C}_2\text{H}_4
C
2
H
4
and
C
4
H
8
\text{C}_4\text{H}_8
C
4
H
8
(3)
N
2
O
4
\text{N}_2\text{O}_4
N
2
O
4
and
NO
2
\text{NO}_2
NO
2
(4)
C
2
H
2
\text{C}_2\text{H}_2
C
2
H
2
and
C
6
H
6
\text{C}_6\text{H}_6
C
6
H
6
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