Mathematics

Mathematics

Problem

Let α\alpha, β\beta, γ\gamma be the three roots of the equation x3+bx+c=0x^3 + bx + c = 0. If βγ=1=−α\beta\gamma = 1 = -\alpha, then b3+2c3−3α3−6β3−8γ3b^3 + 2c^3 - 3\alpha^3 - 6\beta^3 - 8\gamma^3 is equal to (a) 21 (b) 1698\frac{169}{8} (c) 19 (d) 1558\frac{155}{8}

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