Chemistry

Problem

Calculate the radius of the

n=2

orbit of singly–ionised helium (

\mathrm{He}^{+}

Z=2

). (Bohr radius

a_0 = 0.529\,\text{Å}

;

1\,\text{Å}=10^{-10}\,\text{m}

) a)

2.12\times10^{-10}\,\text{m}

1.06\times10^{-10}\,\text{m}

0.529\times10^{-10}\,\text{m}

0.265\times10^{-10}\,\text{m}