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Mathematics
Problem
The function
g
(
x
)
=
ln
(
2
x
+
1
)
g(x)=\ln(2x+1)
g
(
x
)
=
ln
(
2
x
+
1
)
is differentiable for
x
>
−
1
2
x>-\tfrac12
x
>
−
2
1
. Which of the following is the equation of the line tangent to the graph of
g
g
g
at
x
=
1
x=1
x
=
1
? a)
y
=
ln
3
+
2
5
(
x
−
1
)
y=\ln 3+\dfrac{2}{5}(x-1)
y
=
ln
3
+
5
2
(
x
−
1
)
b)
y
=
ln
3
+
2
3
(
x
−
1
)
y=\ln 3+\dfrac{2}{3}(x-1)
y
=
ln
3
+
3
2
(
x
−
1
)
c)
y
=
2
3
(
x
−
1
)
y=\dfrac{2}{3}(x-1)
y
=
3
2
(
x
−
1
)
d)
y
=
ln
3
+
1
3
(
x
−
1
)
y=\ln 3+\dfrac{1}{3}(x-1)
y
=
ln
3
+
3
1
(
x
−
1
)
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