Mathematics

Mathematics

Problem

Differentiate y=5x4−2x2+3sin⁡x−4cos⁡xy=5x^{4}-2x^{2}+3\sin x-4\cos x and hence find y′y' at x=π2x=\dfrac{\pi}{2}. a) 5π32+2π+4\dfrac{5\pi^{3}}{2}+2\pi+4 b) 5π32−2π\dfrac{5\pi^{3}}{2}-2\pi c) 5π32−2π+4\dfrac{5\pi^{3}}{2}-2\pi+4 d) 5π32−2π−4\dfrac{5\pi^{3}}{2}-2\pi-4

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