Mathematics

Mathematics

Problem

Let the functions f:R→Rf: \mathbb{R} \to \mathbb{R} and g:R→Rg: \mathbb{R} \to \mathbb{R} be defined by f(x)=ex−1−e−∣x−1∣f(x) = e^{x-1} - e^{-|x-1|} and g(x)=12(ex−1+e1−x)g(x) = \frac{1}{2}(e^{x-1} + e^{1-x}). Then the area of the region in the first quadrant bounded by the curves y=f(x)y = f(x), y=g(x)y = g(x) and x=0x = 0 is: [JEE-Advanced 2020] (A) (2−3)+12(e−e−1)(2 - \sqrt{3}) + \frac{1}{2}(e - e^{-1}) (B) (2+3)+12(e−e−1)(2 + \sqrt{3}) + \frac{1}{2}(e - e^{-1}) (C) (2−3)+12(e+e−1)(2 - \sqrt{3}) + \frac{1}{2}(e + e^{-1}) (D) (2+3)+12(e+e−1)(2 + \sqrt{3}) + \frac{1}{2}(e + e^{-1})

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