JEE Advanced 2012 Paper 2 Mathematics Q2

Mathematics

Problem

Let PQRPQR be a triangle of area Δ\Delta with a=2a=2, b=72b=\dfrac72 and c=52c=\dfrac52, where aa, bb and cc are the lengths of the sides of the triangle opposite to the angles at PP, QQ and RR respectively. Then 2sin⁡P−sin⁡2P2sin⁡P+sin⁡2P\dfrac{2\sin P-\sin2P}{2\sin P+\sin2P} equals

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