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Mathematics
Mathematics
Problem
Let the line
x
−
2
3
=
y
−
1
−
5
=
z
+
2
2
\frac{x-2}{3} = \frac{y-1}{-5} = \frac{z+2}{2}
3
x
−
2
=
−
5
y
−
1
=
2
z
+
2
lies in the plane
x
+
3
y
−
α
z
+
β
=
0
x + 3y - \alpha z + \beta = 0
x
+
3
y
−
α
z
+
β
=
0
. Then,
(
α
,
β
)
(\alpha, \beta)
(
α
,
β
)
equals a.
(
6
,
−
17
)
(6, -17)
(
6
,
−
17
)
b.
(
−
6
,
7
)
(-6, 7)
(
−
6
,
7
)
c.
(
5
,
−
15
)
(5, -15)
(
5
,
−
15
)
d.
(
−
5
,
15
)
(-5, 15)
(
−
5
,
15
)
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