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Mathematics
Mathematics
Problem
If
tan
θ
2
=
a
−
b
a
+
b
tan
ϕ
2
\tan \frac{\theta}{2} = \sqrt{\frac{a-b}{a+b}} \tan \frac{\phi}{2}
tan
2
θ
=
a
+
b
a
−
b
tan
2
ϕ
, prove that,
cos
θ
=
a
cos
ϕ
+
b
a
+
b
cos
ϕ
\cos \theta = \frac{a \cos \phi + b}{a + b \cos \phi}
cos
θ
=
a
+
b
cos
ϕ
a
cos
ϕ
+
b
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