If cos⁡3θ(1−sin⁡θ)+sin⁡3θ(1+cos⁡θ)=1+cos⁡θ\frac{\cos^3 \theta}{(1 - \sin \theta)} + \frac{\sin^3 \theta}{(1 + \cos \theta)} = 1 + \cos \theta…

Problem

If cos⁡3θ(1−sin⁡θ)+sin⁡3θ(1+cos⁡θ)=1+cos⁡θ\frac{\cos^3 \theta}{(1 - \sin \theta)} + \frac{\sin^3 \theta}{(1 + \cos \theta)} = 1 + \cos \theta , then number of possible values of θ\theta is (where θ∈[0,2π]\theta \in [0, 2\pi] ).

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