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Mathematics
Mathematics
Problem
Consider
d
N
d
t
=
−
0.6
N
(
15
−
N
)
\dfrac{dN}{dt}=-0.6N\,(15-N)
d
t
d
N
=
−
0.6
N
(
15
−
N
)
with
N
>
0
N>0
N
>
0
. For which initial value of
N
N
N
is
d
N
d
t
\dfrac{dN}{dt}
d
t
d
N
positive at
t
=
0
t=0
t
=
0
? a)
N
(
0
)
=
15
N(0)=15
N
(
0
)
=
15
b)
N
(
0
)
=
20
N(0)=20
N
(
0
)
=
20
c)
N
(
0
)
=
5
N(0)=5
N
(
0
)
=
5
d)
N
(
0
)
=
10
N(0)=10
N
(
0
)
=
10
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