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Mathematics
Mathematics
Problem
Show that
∑
k
=
1
n
(
6
k
+
4
)
=
3
n
(
n
+
1
)
+
4
n
\displaystyle \sum_{k=1}^{n}(6k+4)=3n(n+1)+4n
k
=
1
∑
n
(
6
k
+
4
)
=
3
n
(
n
+
1
)
+
4
n
.
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