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Physics
Physics
Problem
The rate of heat flow
d
Q
d
t
\dfrac{dQ}{dt}
d
t
d
Q
through a uniform slab of cross-sectional area
A
A
A
, thickness
L
L
L
and thermal conductivity
k
k
k
for a temperature difference
Δ
T
\Delta T
Δ
T
between its faces is proportional to a)
2
k
A
Δ
T
L
\displaystyle \frac{2kA\,\Delta T}{L}
L
2
k
A
Δ
T
b)
k
A
Δ
T
2
L
\displaystyle \frac{kA\,\Delta T}{2L}
2
L
k
A
Δ
T
c)
k
A
Δ
T
L
\displaystyle \frac{kA\,\Delta T}{L}
L
k
A
Δ
T
d)
3
2
k
A
Δ
T
L
\displaystyle \frac{3}{2}\,\frac{kA\,\Delta T}{L}
2
3
L
k
A
Δ
T
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