Principles of Quantum Mechanics · Problem 12.3.8

Rotational Invariance and Angular Momentum — R. Shankar

Physics — Quantum Mechanics · charged-particle-magnetic-field

Problem

Consider a particle of charge qq in a vector potential A=B2(−yi+xj)\mathbf{A} = \frac{B}{2}(-y\mathbf{i} + x\mathbf{j}) (1) Show that the magnetic field is B=Bk\mathbf{B} = B\mathbf{k}. (2) Show that a classical particle in this potential will move in circles at an angular frequency ω0=qB/μc\omega_0 = qB/\mu c. (3) Consider the Hamiltonian for the corresponding quantum problem: H=[Px+qYB/2c]22μ+[Py−qXB/2c]22μH = \frac{[P_x + qYB/2c]^2}{2\mu} + \frac{[P_y - qXB/2c]^2}{2\mu} Show that Q=(cPx+qYB/2)/qBQ = (cP_x + qYB/2)/qB and P=(Py−qXB/2c)P = (P_y - qXB/2c) are canonical. Write HH in terms of PP and QQ and show that allowed levels are E=(n+1/2)ℏω0E = (n+1/2)\hbar\omega_0. (4) Expand HH out in terms of the original variables and show H=H(ω02,μ)−ω02LzH = H\left(\frac{\omega_0}{2}, \mu\right) - \frac{\omega_0}{2} L_z where H(ω0/2,μ)H(\omega_0/2, \mu) is the Hamiltonian for an isotropic two-dimensional harmonic oscillator of mass μ\mu and frequency ω0/2\omega_0/2. Argue that the same basis that diagonalized H(ω0/2,μ)H(\omega_0/2, \mu) will diagonalize HH. By thinking in terms of this basis, show that the allowed levels for HH are E=(k+12∣m∣−12m+12)ℏω0E = (k + \frac{1}{2}|m| - \frac{1}{2}m + \frac{1}{2})\hbar\omega_0, where kk is any integer and mm is the angular momentum. Convince yourself that you get the same levels as from the earlier formula [E=(n+1/2)ℏω0][E = (n+1/2)\hbar\omega_0]. We shall return to this problem in Chapter 21.

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