Mathematics

Problem

\sin \theta=\dfrac{3}{5}

and

\theta

lies in the first quadrant, find the value of

\displaystyle \frac{1 - \sin^{2}\theta}{\sin \theta \cos \theta}

. a)

\dfrac{5}{3}

\dfrac{3}{4}

\dfrac{4}{3}

\dfrac{5}{6}