Problem

Problem

If 2cos⁡A=cos⁡B+cos⁡3B\sqrt{2} \cos A = \cos B + \cos^3 B , and 2sin⁡A=sin⁡B−sin⁡3B\sqrt{2} \sin A = \sin B - \sin^3 B then sin⁡(A−B)=\sin(A - B) = a. ±1\pm 1 b. ±12\pm \frac{1}{2} c. ±13\pm \frac{1}{3} d. ±14\pm \frac{1}{4}

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