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Problem
Problem
The solution of the equation
sin
2
x
+
sin
4
x
=
2
sin
3
x
\sin 2x + \sin 4x = 2 \sin 3x
sin
2
x
+
sin
4
x
=
2
sin
3
x
is a.
x
=
n
π
3
x = \frac{n\pi}{3}
x
=
3
nπ
b.
x
=
n
π
x = n\pi
x
=
nπ
c.
x
=
2
n
π
x = 2n\pi
x
=
2
nπ
d. None of the above
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