Mathematics

Mathematics

Problem

∫xsin⁡xsec⁡3x dx=\int x \sin x \sec^3 x \, dx = (a) 12[sec⁡2x−tan⁡x]+c\frac{1}{2} [\sec^2 x - \tan x] + c (b) 12[xsec⁡2x−tan⁡x]+c\frac{1}{2} [x \sec^2 x - \tan x] + c (c) 12[xsec⁡2x+tan⁡x]+c\frac{1}{2} [x \sec^2 x + \tan x] + c (d) 12[sec⁡2x+tan⁡x]+c\frac{1}{2} [\sec^2 x + \tan x] + c (a) 12[sec⁡2x−tan⁡x]+c\frac{1}{2} [\sec^2 x - \tan x] + c (b) 12[xsec⁡2x−tan⁡x]+c\frac{1}{2} [x \sec^2 x - \tan x] + c (c) 12[xsec⁡2x+tan⁡x]+c\frac{1}{2} [x \sec^2 x + \tan x] + c (d) 12[sec⁡2x+tan⁡x]+c\frac{1}{2} [\sec^2 x + \tan x] + c

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