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Mathematics
Mathematics
Problem
Determine
lim
x
→
5
−
x
2
−
25
3
x
−
15
\displaystyle\lim_{x\to5^{-}}\frac{x^{2}-25}{3x-15}
x
→
5
−
lim
3
x
−
15
x
2
−
25
and state, with brief justification, whether the function
g
(
x
)
=
x
2
−
25
3
x
−
15
g(x)=\frac{x^{2}-25}{3x-15}
g
(
x
)
=
3
x
−
15
x
2
−
25
can be redefined at
x
=
5
x=5
x
=
5
to make it continuous there.
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