Mathematics

Mathematics

Problem

In △ABC\triangle ABC, DD is the midpoint of ABAB. A point EE on ACAC is chosen so that DE∥BCDE \parallel BC. If AC=16 cmAC = 16\,\text{cm}, then AEAE equals a) 323 cm\dfrac{32}{3}\,\text{cm} b) 8 cm8\,\text{cm} c) 12 cm12\,\text{cm} d) 163 cm\dfrac{16}{3}\,\text{cm}

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