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Mathematics
Problem
The eccentricity of the hyperbola conjugate to
x
2
−
3
y
2
=
2
x
+
8
x^2 - 3y^2 = 2x + 8
x
2
−
3
y
2
=
2
x
+
8
is a.
2
3
\frac{2}{\sqrt{3}}
3
2
b.
3
\sqrt{3}
3
c.
2
2
2
d.
2
\sqrt{2}
2
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